Consider the following expressions
I have used i, the complex number in both.
One gives a simple cos(x) expressions. While the other cosh(x). This is a discovery.
Another point is, now I think I am in a position to get sigma integral equivalence for trigonometric and hyperbolic functions.
Have a nice day!!
4 comments:
No. A simple sigma integral equivalence for all trigonometric functions is not possible. To me.
If sin(x) and cos(x) are meant to be in a right triangle then there should not be much problem as sin(pi by 2 minus x) is cos(x) and vice versa.
But sin(x) and cos(x) are so beautiful. They have properties which resemble nature so well. In electrical engineering for example.
In my vision and opinion integral of cos(x) cannot be made into sigma equivalence. It is futile. Because cos(x) is of horizontal.
I used binomial expressions along with hypergeometric functions because:-
1. I had an urge to do more with hypergeometric functions as I seemed to have got 1 to 1 mapping between hypergeometric functions and hypergeometric distribution.
2. I had a simple e model
3. Wolfram alpha supports my statements.
I am not totally zero in higher mathematics.
I had courses in engineering mathematics during B E .
This finishes the discussion. The forum is closed.
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