Calculating 4.73715 ! with only sigma operation

Here is how one can calculate 4.73715! with my formulas.

I came to know only yesterday using Math GPT. That is height of 'Agyaanatha'. It may not be necessary to use integrals for decimal factorial calculations.

Have a nice day !!

Two results in recent times

 I made two expressions in recent times. One more golden ratio formula. And one n! formula.

Golden ratio formula

n! formula

These I have made in recent few days. I hope you like the above expressions.

Have a nice day !!

My mother and I

I am staying with my mother here in Ranchi. 

She has been staying here with me since 2017. I was transferred to RDCIS,  Ranchi in 2016. 

She was helping me with food and managing the quarters we live in. But currently she is under medicine . It may probably take a month for her to become better.

Currently we are managing food from SAIL mess here in Ranchi. SAIL has good facilities and SAIL staff are helpful. 

Have a nice day, my blog friends. 

My complete 4.666 expressions

Here is what I did

Integral at n = 33.333 (proposed. This formula is okayish if we replace 33.333 by numbers from 5 to 50. The factorials between 10 and 100 can be calculated.)

Actual value of 66.666! ((2*33.333)!)

These are the complete statements on 4.666 thing that I blogged about two days back.

This finishes on 4.666 number.

The results for 212 with a bigger polynomial correction.

Do aur do paanch (2+2=5)?

In earlier times people were indiscriminately using negatives of numbers and came up with statements like 2+2=5.

Also during those days mathematicians were contemplating of root of minus 1.

Maclaurin had come up with infinite series of sin(x), cos(x) and also log(x). These do not require 0 factorial (0!). Maclaurin could have managed without 0!.

Euler took upon his shoulders the 0!. He also introduced i, the complex number which is root of minus 1. The e constant was born.

"External " binomial expressions (a+b)^n were made by Newton. Newton used his thumb as 1, as a right triangle and also placed it in ground indicating use of gravity. Three things Newton used his thumb for. He was a super human. 

Newton's mathematics were spread on all the  areas where the "sun never sets".

X=0 is a sin in mathematics.  What to say of polynomials equated to 0. Personally I was looking out for m squared minus m minus 1 sorts of expressions but rarely equated them to zero in mind.

I hope my sins are forgot. 

Drawing books I wish to buy

In mathematics I wish to learn partial sums and hypergeometry. 

My feelings for expressing myself and nature surrounding us is over. With my earlier blog post.

I wish to buy the following books on drawing. 

The zero(0) and zero factorial (0!)

I have felt many Indian intellectuals involving in zero(0) and zero factorial (0!). These intellectuals feel they are zero(0), as they have absence of ego. But the same gentlemen take decisions and actions of zero factorial (0!). Top decisions and top actions. Number 1 decisions and Number 1 actions. 

These intellectuals fail to realize that the zero (0) is of the ruler or scale. Not their internals.

I have been busy with n!, 2n!, ((n+1)(n+2))/2 thoughts and expressions.  All these expressions start from 1. There is no zero(0). I suggest Indian intellectuals to take advantage of these expressions and develop models of thought.  I feel the results are fascinating and good. I have a e to the power of x and log(x) type of equivalent expressions.  Yes, my expressions seem good to me and there is scope of something big. But I need help and guidance and cooperation from Professors. Because the concept may be tough.

You may recall my binomial start from 1 and there are decent expressions. 

Only thing is I need help from Indian mathematicians.  

Let us forget zero(0) and zero factorial (0!). Let us work with 1. Let us remove confusion.

Google blog friends, if possible help me with a group of mathematical intellectuals.  If I can join them, I shall be grateful and thankful.

This is what I meant.

Hope you understood the approximate equivalence (in my case) to the similar e and log relations.

If you want clarifications, do comment below.

It works.

Sigma of (((((n+1)(n+2))/2)^n)/((2n)!)*(1/x)^n, summed up from 0 to infinity equals approximately (4.666)^(1/x). Also sum of ((1/x)^n)/(n(n+1) alternately negated, from 1 to infinity gives (n+1)*ln((n+1)/n)-1. Substituting n as 4.666, 4.666 *2, 4.666*3 . . .  gives 0.1, 0.1/2, 0.1/3, .....

Please confirm. It seems amazing. The results. 

The results are approximate. 

Here are some more details

The results are approximate.  But fascinating.  Thank you, my Lord, Jesus Christ. 

I have typed in MS Word the relevant formulas.

I propose multiplying the LHS of third expression in the just above image by (4.666/5) to get better 0.1/n (RHS) accuracy.

Apart from that I do not recommend any more changes. No changes of 4.66 factor. Also I don't want to invest my mind in exploring the why's of (4.666)^(1/y).

I believe God wants it this way.

For very large values the results are inconsistent.  This is because of string theory.

See below the inconsistent result.

Remember the famous

1+2+3+4+.............. =-1/12. Yes. String theory. 

I believe it comes negated because of Jesus Christ and Anno Domini time. Mental faculties can't work to this level. But Jesus Christ and his time and the inventions by his followers like pen, paper, calculator makes seeing this phenomenon.