This formula is important. This is because the formula is correct only at n =pi near abouts.
The formula is correct when n = 3.06 and 2n is considered 6.2895. Below this value n has to be decreased to get 2n!. And above this value n has to be increased to get 2n! value. I am talking of positive integers.
Then this formula has to be corrected for 1 to 0 numbers.
There are 3 or 4 things to do to use the above factor. But as this is of pi, I will try in the coming days.
You may also try as pi is nature constant.
Have a nice day !!
2 comments:
I have discovered that multiplication with
(1.0247)^(4n -8*pi)
the above
((n+1)(n+2)/2)^n
gives appropriate factorial of 2n from 1 to 47.
If one varies the 4 of 4n in (1.0247)^(4n-8*pi) in the range of 3.5 to 4.5 then one can get accepted 2n!.
The 4 in 4n is therefore the ceiling or floor value.
2n from 1 to 170 checked randomly.
I.e. n from 0.5 to 85.
You need not check further. And get wild and mad at me !! 🤣🤣🤣
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